我正在使用 redux-toolkit prepare 函数来构建最终的有效负载值。

    addTodo: {
      reducer: (state, action) => {
        state.push(action.payload);
      },
      // ERROR: **Type '{ payload: Todo; }' is missing the following properties from type 'Omit<PayloadAction<any, string, any, any>, "type">': meta, errorts**
      prepare: (todoMessage: string): { payload: Todo } => {
        return {
          payload: { message: todoMessage, id: uuid(), completed: false }
        };
      }
    },

如何键入 prepare 函数来消除 typescript 错误？

检查错误here .

最佳答案

    addTodo: {
      reducer: (state, action: PayloadAction<Todo>) => {
        state.push(action.payload);
      },
      prepare: (todoMessage: string) => {
        return {
          payload: { message: todoMessage, id: uuid(), completed: false }
        };
      }
    },

您只需要在action 上添加一个负载类型。

关于javascript - 如何在 redux-toolkit 中输入 'prepare' 函数，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/72486092/