我是 Python 和编程新手。我正在尝试制作一个程序来验证输入的密码是否具有特定格式。我很确定我的代码是正确的，但显然......它不是。当密码格式正确时，它不会退出 while 循环。 我的错误在哪里？感谢大家的耐心等待!

low = ['abcdefghijklmnopqrstuvwxyz']
up = ['ABCDEFGHIJKLMNOPQRSTUVWXYZ']
cr = ['@$%&']
digito = ['0123456789']
counter1 = 0
tries = True
while tries:
    length = False
    May = False
    Minus = False
    Num = False
    Char = False
    counter1 += 1
    password = input('Password: ')
    if len(password) > 7 and len(password) < 16:
        length = True
    for caracter in password:
        if caracter in low:
            Minus = True
        if caracter in up:
            May = True
        if caracter in cr:
            Char = True
        if caracter in digito:
            Num = True
    if length and May and Minus and Num and Char:
        print('Password ok.')
        passw = password
        tries = False
    if counter1 == 5:
        print('You had 5 attemps.')
        break

最佳答案

问题是当您检查时:

"A" in ['ABCDEFGHIJKLMNOPQRSTUVWXYZ']

它返回 False。这是因为列表 ['ABCDEFGHIJKLMNOPQRSTUVWXYZ'] 不包含元素 "A"。尝试用以下代码替换前 4 行，看看它是否有效:

low = 'abcdefghijklmnopqrstuvwxyz'
up = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
cr = '@$%&'
digito = '0123456789'

https://stackoverflow.com/questions/72604770/