我尝试将Grails 1.3.7与插件gorm-jpa 0.7.1结合使用，以使用EclipseLink 2.2.0作为持久性提供程序来启用JPA持久性。

当运行应用程序并单击带有JPA注释的实体的 Controller 时，我从EclipseLink的JPQLParser获得了“UnwantedTokenException”:

Executing action [list] of controller [model.PersonController] caused exception:
An exception occurred while creating a query in EntityManager:
Exception Description: Syntax error parsing the query [select person from model.Person as person ], line 1, column 24: syntax error at [.].
Internal Exception: UnwantedTokenException(found=., expected 80);
  at org.eclipse.persistence.internal.libraries.antlr.runtime.BaseRecognizer.recoverFromMismatchedToken(BaseRecognizer.java:587)
  [...]
  at org.eclipse.persistence.internal.jpa.parsing.jpql.JPQLParser.parse(JPQLParser.java:134)

grails create-app GrailsJPA
cd GrailsJPA
grails uninstall-plugin hibernate
grails install-plugin gorm-jpa
grails create-domain-class model.Person

package model

import javax.persistence.*;

@Entity
class Person {

    @Id
    @GeneratedValue
    long id;

    @Basic
    long version;

    @Basic
    String firstName

    @Basic
    String lastName

    static constraints = {
        firstName(nullable:true)
        lastName(nullable:true)
    }

}

grails generate-controller model.Person
grails generate-view model.Person

beans = {

    entityManagerFactory(org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean) {
        beanClassLoader = ref("classLoader")
        dataSource = ref("dataSource")
        loadTimeWeaver = new org.springframework.instrument.classloading.SimpleLoadTimeWeaver()
    }

    transactionManager(org.springframework.orm.jpa.JpaTransactionManager) {
        entityManagerFactory = entityManagerFactory
    }

}

<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0">
    <persistence-unit name="manager" transaction-type="RESOURCE_LOCAL">
        <provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
        <class>model.Person</class>
        <properties>
            <property name="eclipselink.ddl-generation" value="create-tables"/>
        </properties>
    </persistence-unit>
</persistence>

lib\eclipselink.jar

grails run-app

http://localhost:8080/GrailsJPA

最佳答案

我设法通过以下方式使EclipseLink 2.3.0 JPA提供程序与不在软件包中的域类一起工作。

在下面的文章中，我将展示如何设置一个Grails应用程序，该应用程序使用EclipseLink作为JPA提供程序来持久化域类并在Tomcat 6 Web容器中运行该应用程序。

开始于

grails create-app GrailsJPA
cd GrailsJPA
grails uninstall-plugin hibernate
grails install-plugin gorm-jpa
grails create-domain-class Person

import javax.persistence.*;

@Entity
class Person {

    @Id
    @GeneratedValue
    long id;

    @Basic
    long version;

    @Basic
    String firstName

    @Basic
    String lastName

    static constraints = {
        firstName(nullable:true)
        lastName(nullable:true)
    }

}

grails generate-controller Person
grails generate-view Person

[...]
def save = {
    Person.withTransaction {
    [...original code stays in this block...]
    }
}
[...]
def edit = {
    Person.withTransaction {
        [...original code stays in this block...]           }
    }
}
def update = {
    Person.withTransaction {
        [...original code stays in this block...]
    }
}
def delete = {
    Person.withTransaction {
        [...original code stays in this block...]
    }
}
[...]

<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0">
    <persistence-unit name="manager" transaction-type="RESOURCE_LOCAL">
        <provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
        <class>Person</class>
        <properties>
            <property name="eclipselink.ddl-generation" value="create-tables"/>
        </properties>
    </persistence-unit>
</persistence>

lib\eclipselink.jar

beans = {

    entityManagerFactory(org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean) {
        dataSource = ref("dataSource")
        beanClassLoader = ref("classLoader")
        loadTimeWeaver = new org.springframework.instrument.classloading.InstrumentationLoadTimeWeaver()
    }

    transactionManager(org.springframework.orm.jpa.JpaTransactionManager) {
        entityManagerFactory = entityManagerFactory
    }

}

if exist "%CATALINA_HOME%\lib\spring-agent-2.5.6.SEC02.jar" set JAVA_OPTS=%JAVA_OPTS% -javaagent:%CATALINA_HOME%\lib\spring-agent-2.5.6.SEC02.jar

<?xml version="1.0" encoding="UTF-8"?>
<Context>
    <Loader loaderClass="org.springframework.instrument.classloading.tomcat.TomcatInstrumentableClassLoader"/>
</Context>

[...]
development {
    dataSource {
        dbCreate = "create-drop"
        url = "jdbc:hsqldb:mem:testDB"
    }
}
test {
    dataSource {
        dbCreate = "create-drop"
        url = "jdbc:hsqldb:mem:testDb"
    }
}
production {
    dataSource {
        dbCreate = "create-drop"
        url = "jdbc:hsqldb:mem:testDB"
    }
}
[...]

grails war

"%CATALINA_HOME%\bin\startup.bat"

http://localhost:8080/GrailsJPA

http://grails.org/Download

http://www.eclipse.org/eclipselink/downloads/2.3.0

http://tomcat.apache.org/download-60.cgi

http://mvnrepository.com/artifact/org.springframework/spring-instrument-tomcat

http://mvnrepository.com/artifact/org.springframework/spring-agent

关于grails - 将Grails 1.3.7与EclipseLink 2.2.0 JPA Provider一起使用，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/7272058/