我正在尝试编译以下程序，并不断收到抽象方法错误。我尝试编译的程序如下(虽然尚未完成)。我收到的错误如下:

Double.java:5: error: Double is not abstract and does not override abstract method getNext() in ListInterface
public class Double<T extends Comparable<T>> implements ListInterface<T>{
       ^
  where T is a type-variable:
    T extends Comparable<T> declared in class Double
1 error

import java.io.*;
import ch06.lists.*;
import support.DLLNode;

public class Double<T extends Comparable<T>> implements ListInterface<T>{

    protected DLLNode<T> front;
    protected DLLNode<T> rear;
    protected DLLNode<T> curPosition;
    protected int numElements;

    public Double(){
        front = null;
        rear = null;
        curPosition = null;
        numElements = 0;
    }

    protected DLLNode<T> find(T target){

    }

    public int size(){
        return numElements;
    }

    public boolean contains(T element) throws NullPointerException{
        if (DLLNode.getInfo()!=element){
            return false;
        }
        else{
            return true;
        }
    }

    public boolean remove(T target) throws StackUnderflowException{
        if (!contains(target)){
            return false;
        }
        else{
            return true;
            DLLNode.setLink()==null;
        }
    }

    public T get(T element){
        return find(element);
    }

    public String toString(){

    }   

    public void reset(){

    }

    @Override
    public T getNext(){
        return null;
    }

    public void resetBack(){

    }

    public T getPrevious(){

    }

    public void add(T element){

    }
}

最佳答案

这里有很多错误。

一些:

1。

 protected DLLNode<T> find(T target){

 public String toString(){

public T getPrevious(){

    protected DLLNode<T> find(T target) {

    public T get(T element) {
        return find(element);
    }

关于java - Double不是抽象的，并且不会重写ListInterface中的抽象方法getNext()吗？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/15908485/