keras - 在不运行模型的情况下计算 Keras 中的损失

有没有办法在不运行评估或拟合的情况下使用当前权重获得模型的损失?

model = keras.Sequential([
    keras.layers.Input(400),
    keras.layers.Dense(25, activation=tf.nn.sigmoid, kernel_regularizer=regularizers.l2(lambd)),
    keras.layers.Dense(10, activation=tf.nn.softmax)
])
model.compile(optimizer='adam',
              loss='sparse_categorical_crossentropy',  # does the 1-hot encoding for us
              metrics=['accuracy'])
model.set_weights([Theta1.T, np.zeros(25), Theta2.T, np.zeros(10)])
prob = model.predict(X)
pred = np.argmax(prob, axis=1).reshape(-1, 1)
pred_y = pred == y
print(f'Training Set Accuracy: {np.mean(pred_y)*100:.2f}%') 
# How do I get the loss now?

This对我不起作用。

最佳答案

您可以通过将 model.predict(x) 的输出传递给损失函数的实现。此外,您还需要一个函数来计算模型正则化损失 - reg_loss(model)。以下是所有层的 binary_crossentropyl1l2l1_l2 损失的实现,包括循环 -但包括 activity_regularizer 损失,这不是体重损失。您可以将 binary_crossentropy 替换为您自己的函数 - 例如sparse_softmax_crossentropy_with_logits:


工作实现:(数值稳定版)

def binary_crossentropy(y_true, y_pred, sample_weight=1):
    if len(y_pred.shape)==1:
        y_pred = np.atleast_2d(y_pred).T
    y_pred = [max(min(pred[0], 1-K.epsilon()), K.epsilon()) for pred in y_pred]
    y_true,y_pred,sample_weight = force_2d_shape([y_true,y_pred,sample_weight])

    logits = np.log(y_pred) - np.log(1-y_pred) # sigmoid inverse
    neg_abs_logits = -np.abs(logits)
    relu_logits    = (logits > 0)*logits

    loss_vec = relu_logits - logits*y_true + np.log(1 + np.exp(neg_abs_logits))
    return np.mean(sample_weight*loss_vec)

def force_2d_shape(arr_list):
    for arr_idx, arr in enumerate(arr_list):
        if len(np.array(arr).shape) != 2:
            arr_list[arr_idx] = np.atleast_2d(arr).T
    return arr_list
def l1l2_weight_loss(model):
    l1l2_loss = 0
    for layer in model.layers:
        if 'layer' in layer.__dict__ or 'cell' in layer.__dict__:
            l1l2_loss += _l1l2_rnn_loss(layer)
            continue

        if 'kernel_regularizer' in layer.__dict__ or \
           'bias_regularizer'   in layer.__dict__:
            l1l2_lambda_k, l1l2_lambda_b = [0,0], [0,0] # defaults
            if layer.__dict__['kernel_regularizer'] is not None:
                l1l2_lambda_k = list(layer.kernel_regularizer.__dict__.values())
            if layer.__dict__['bias_regularizer']   is not None:
                l1l2_lambda_b = list(layer.bias_regularizer.__dict__.values())

            if any([(_lambda != 0) for _lambda in (l1l2_lambda_k + l1l2_lambda_b)]):
                W = layer.get_weights()

                for idx,_lambda in enumerate(l1l2_lambda_k + l1l2_lambda_b):
                    if _lambda != 0:
                        _pow = 2**(idx % 2) # 1 if idx is even (l1), 2 if odd (l2)
                        l1l2_loss += _lambda*np.sum(np.abs(W[idx//2])**_pow)
    return l1l2_loss
def _l1l2_rnn_loss(layer):
    l1l2_loss = 0
    if 'backward_layer' in layer.__dict__:
        bidirectional = True
        _layer = layer.layer
    else:
        _layer = layer
        bidirectional = False
    ldict = _layer.cell.__dict__

    if 'kernel_regularizer'    in ldict or \
       'recurrent_regularizer' in ldict or \
       'bias_regularizer'      in ldict:
        l1l2_lambda_k, l1l2_lambda_r, l1l2_lambda_b = [0,0], [0,0], [0,0]
        if ldict['kernel_regularizer']    is not None:
            l1l2_lambda_k = list(_layer.kernel_regularizer.__dict__.values())
        if ldict['recurrent_regularizer'] is not None:
            l1l2_lambda_r = list(_layer.recurrent_regularizer.__dict__.values())
        if ldict['bias_regularizer']      is not None:
            l1l2_lambda_b = list(_layer.bias_regularizer.__dict__.values())

        all_lambda = l1l2_lambda_k + l1l2_lambda_r + l1l2_lambda_b
        if any([(_lambda != 0) for _lambda in all_lambda]):
            W = layer.get_weights()
            idx_incr = len(W)//2 # accounts for 'use_bias'

            for idx,_lambda in enumerate(all_lambda):
                if _lambda != 0:
                    _pow = 2**(idx % 2) # 1 if idx is even (l1), 2 if odd (l2)
                    l1l2_loss += _lambda*np.sum(np.abs(W[idx//2])**_pow)
                    if bidirectional:
                        l1l2_loss += _lambda*np.sum(
                                    np.abs(W[idx//2 + idx_incr])**_pow)
        return l1l2_loss  


测试实现:

from keras.layers import Input, Dense, LSTM, GRU, Bidirectional
from keras.models import Model
from keras.regularizers import l1, l2, l1_l2
import numpy as np 

ipt   = Input(shape=(1200,16))
x     = LSTM(60, activation='relu', return_sequences=True,
                                                 recurrent_regularizer=l2(1e-3),)(ipt)
x     = Bidirectional(GRU(60, activation='relu', bias_regularizer     =l1(1e-4)))(x)
out   = Dense(1,  activation='sigmoid',          kernel_regularizer   =l1_l2(2e-4))(x)
model = Model(ipt,out)

model.compile(loss='binary_crossentropy', optimizer='adam')
X = np.random.rand(10,1200,16) # (batch_size, timesteps, input_dim)
Y = np.random.randint(0,2,(10,1))
class_weights = {'0':1, '1': 6}
sample_weights = np.array([class_weights[str(label[0])] for label in Y])
keras_loss   = model.evaluate(X,Y,sample_weight=sample_weights)
custom_loss  = binary_crossentropy(Y, model.predict(X))
custom_loss += l1l2_weight_loss(model)

print('%.6f'%keras_loss  + ' -- keras_loss')
print('%.6f'%custom_loss + ' -- custom_loss') 

0.763822 -- keras_loss
0.763822 -- 自定义损失

https://stackoverflow.com/questions/57975763/

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