我尝试搜索，但找不到任何对我有意义的东西!我是正则表达式的菜鸟 :)

尝试查看另一个字符串中是否存在特定单词“some_text”。

String s = "This is a test() function"
String s2 = "This is a test    () function"

[^\w]test[ ]*[(]

System.out.println(s.matches("[^\\w]test[ ]*[(]");

最佳答案

您缺少的一点是 Java matches() 为您在 Regex 的开头和末尾放置了一个 ^ $ 。所以你的表达实际上被视为:

^[^\w]test[ ]*[(]$

(?:.*)(?<=\s)(test(?:\s+)?\()(?:.*)

^                 Start of line - added by matches()
(?:.*)            Non-capturing group - match anything before the word, but dont capture into a group
(?<=\s)           Positive lookbehind - match if word preceded by space, but dont match the space
(                 Capturing group $1
  test(?:\s+)?    Match word test and any following spaces, if they exist
  \(              Match opening bracket
)                 
(?:.*)            Non-capturing group - match rest of string, but dont capture in group
$                 End of line - added by matches()

public class Main {
    public static void main(String[] args) {
        String s = "This is a test() function";
        String s2 = "This is a test    () function";
        System.out.println(s.matches("(?:.*)((?<=\\s))(test(?:\\s+)?\\()(?:.*)")); 
        //true
    }
}

https://stackoverflow.com/questions/60464842/