我想使用 javascript 验证一个范围
任何有 $ 符号的范围都必须说无效
任何具有除 : 之外的符号的范围字符串必须说无效
可接受的字符是大写或小写字母和 0-9 数字

一些预期的结果

A0  // invalid range begins with 1 
ZZ12    // valid  
ZZ12:   // invalid incorrectly terminated 
:A11    // invalid incorrectly started 
:1  // invalid incorrectly started 
:A  // invalid incorrectly started 
A1  // valid  
B1  // valid  
A2  // valid  
C:F // valid  
A10:B10 // valid  
A:B10   // valid  
A10:B   // valid  
A:B // valid  
10:10   // valid  
AA1 // valid  
AAA1    // valid  
B9:B10  // valid  
A   // invalid incomplete range string 
1   // invalid incomplete range string 
B   // invalid incomplete range string 
20  // invalid only a number not allowed 
@   // invalid symbols not allowed 
##  // invalid symbols not allowed 
        

我试过

["A0","ZZ12","ZZ12:",":A11",":1",":A","A1","B1","A2","C:F","A10:B10","A:B10","A10:B","A:B","10:10","AA1","AAA1","B9:B10","A","1","B","20","@","##"]
.map(zz=>{return zz + "--->" + /^[A-Z]?[0-9]?:[A-Z]?[0-9]?$/.test(zz)})

最佳答案

此解决方案应满足您的所有要求，包括非零数字:

const regex = /^(?:[A-Z]+[1-9][0-9]*|[A-Z]+(?:[1-9][0-9]*)?:[A-Z]+(?:[1-9][0-9]*)?|[1-9][0-9]*:[1-9][0-9]*)$/;

["A0","ZZ12","ZZ12:",":A11",":1",":A","A1","B1","A2","C:F","A10:B10","A:B10","A10:B","A:B","10:10","1:999","0:1","AA1","AAA1","B9:B10","A","1","B","20","@","##"
].map(str => {
  //let valid = regex.test(str);
  let valid = str.match(regex);
  console.log(str, '==>', valid ? 'ok' : 'invalid');
});

正则解释:

• ^(?: -- 字符串开始和非捕获组开始
  • [A-Z]+[1-9][0-9]* -- 1+个字母，数字从1开始
• | -- 逻辑或
  • [A-Z]+(?:[1-9][0-9]*)?:[A-Z]+(?:[1-9][0-9]*)? -- 1+个字母，可选数字从1开始，: , 1+个字母, 可选数字从1开始
• | -- 逻辑或
  • [1-9][0-9]*:[1-9][0-9]* -- 1+个字母，数字从1开始，: , 1+个字母，从1开始的数字
• )$ -- 非捕获组和字符串结束

https://stackoverflow.com/questions/75013663/