我想确保我只打印最多 80 个字符的长行，但我有一个字符串 s 可以比它更短也可以更长。所以我想将它拆分成行而不拆分任何单词。

长字符串示例:

s = "This is a long string that is holding more than 80 characters and thus should be split into several lines. That is if everything is working properly and nicely and all that. No mishaps no typos. No bugs. But I want the code too look good too. That's the problem!"

我可以想出一些方法来做到这一点，例如:

words = s.split(" ")
line = ""
for w in words:
    if len(line) + len(w) <= 80:
        line += "%s " % w
    else:
        print line
        line ="%s " % w

print line

同样，我可以在 while 循环中迭代地使用 s.find(""):

sub_str_left = 0
pos = 0
next_pos = s.find(" ", pos)
while next_pos > -1:
    if next_pos - sub_str_left > 80:
        print s[sub_str_left:pos-sub_str_left]
        sub_str_left = pos + 1

    pos = next_pos
    next_pos = s.find(" ", pos)

print s[sub_str_left:]

这些都不是很优雅，所以我的问题是是否有更酷的 pythonic 方式来做到这一点？ (也许使用正则表达式。)

最佳答案

有一个模块:textwrap

例如，您可以使用

print '\n'.join(textwrap.wrap(s, 80))

或

print textwrap.fill(s, 80)

https://stackoverflow.com/questions/9968173/