我得到错误: init 方法调用失败;嵌套异常是 org.hibernate.MappingException: Repeated column in mapping for entity: com.messagemanager.domain.User column: id (should be mapped with insert="false"update="false")
有我的实体:
@MappedSuperclass
public abstract class BaseEntity{
@Id
@Column(nullable = false, unique = true, name = "id", insertable = false, updatable = false)
@GeneratedValue(strategy= GenerationType.AUTO)
private Long id;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
}
@Entity
@Table(name = "User")
public class User extends BaseEntity implements Serializable{
@Column(name = UserFieldsKey.ID, length = 50, nullable = false)
private String name;
@Column(updatable = false, insertable = false)
@Transient
private List<Message> listMessage = new ArrayList<>();
public static class UserFieldsKey{
public static final String NAME = "name";
}
public User() {
}
@OneToMany(fetch = FetchType.EAGER, mappedBy = "user")
public List<Message> getListMessage() {
return listMessage;
}
public void setListMessage(List<Message> listMessage) {
this.listMessage = listMessage;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
@Entity
@Table(name = "Message")
public class Message extends BaseEntity implements Serializable{
@Column(name = MessageFieldsKey.MESSAGE, length = 500, nullable = false)
private String message;
@ManyToOne(cascade=CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(name="user")
private User user;
@Column(name = "id_user")
private Long id_user;
public Long getId_user() {
return id_user;
}
public void setId_user(Long id_user) {
this.id_user = id_user;
}
public static class MessageFieldsKey{
public static final String MESSAGE = "mes";
}
public String getMessage() {
return message;
}
public User getUser() {
return user;
}
public Message() {
}
public Message(String message, User user) {
this.message = message;
this.user = user;
}
public void setMessage(String message) {
this.message = message;
}
public void setUser(User user) {
this.user = user;
}
}
有什么想法吗?
附言非常感谢!
最佳答案
看起来那是因为你有这个:
@ManyToOne(cascade=CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(name="user")
private User user;
这将映射到 User.id
;在 Message
中你已经有了一个 id
因为你正在扩展 BaseEntity
关于java - 我收到错误 : Invocation of init method failed; nested exception is org. hibernate.MappingException: Repeated column in mapping for entity,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43231143/
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