我尝试使用 Process Builder 来执行 git 命令。 但它似乎对任何命令都不起作用。

git log 给我正确的结果。

git shortlog -s 但以超时结束!

在终端中运行的两个命令都提供了正确的结果! 我已经在 Win 和 Mac 上测试过了。

有谁知道我该如何调试它，或者我的错误在哪里？

或者也许是不同的解决方案？ 目的是将提交者读出到 git 存储库中的特定文件。

事实上 Git 命令是 git shortlog -s -p FeilePath ?

我的测试代码:

 @Test
    public void testCommandListDir() {

        File execDir = new File("./");
        String returnValue = "";

        try {
            returnValue = runCommand(execDir, 10, TimeUnit.SECONDS, "git", "log");
        } catch (IOException e) {
            e.printStackTrace();
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        assertTrue(returnValue.contains("+ try and error for git shortlog"));
    }


    @Test
    public void testCommandGitShortlog() {

        File execDir = new File("./");
        String returnValue = "";

        try {
            returnValue = runCommand(execDir, 10, TimeUnit.SECONDS, "git", "shortlog", "-s");
        } catch (IOException e) {
            e.printStackTrace();
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        assertTrue(returnValue.equals(""));
    }

    public static String runCommand(File directory, long timeout, TimeUnit unit, String... command) throws IOException, InterruptedException {

        StringBuilder sb = new StringBuilder();

        ProcessBuilder pb = new ProcessBuilder(command)
                .redirectErrorStream(true).directory(directory);


        Process p = pb.start();

        InputStream is = p.getInputStream();
        InputStream es = p.getErrorStream();
        BufferedReader br = new BufferedReader(new InputStreamReader(is));
        BufferedReader bre = new BufferedReader(new InputStreamReader(es));
        String in;

        boolean timeOut = false;


        if (!p.waitFor(timeout, unit)) {
            //timeout - kill the process.
            p.destroy(); // consider using destroyForcibly instead
            timeOut = true;
        }

        if (timeOut) {
            //write time out msg
            sb.append("RunCommand time out! after " + timeout + " " + unit.toString() + "\n");
            sb.append("     directory: " + directory.getAbsolutePath() + "\n");
            sb.append("     command: " + command + "\n");
        } else {
            while ((in = br.readLine()) != null) {
                sb.append(in + "\n");
            }

            while ((in = bre.readLine()) != null) {
                sb.append(in + "\n");
            }
        }
        return sb.toString();
    }

最佳答案

如果我没理解错的话，你正在尝试你的目标是git blame <filepath> .

我建议使用 Git API for Java (JGit)。在这个cookbook ，有几个关于如何开始的例子。

更具体地说，您可以在给定的提交中归咎于给定的文件，如下所示:

private BlameResult blameCommit(String path, RevCommit commitToBlame) throws GitAPIException {
    BlameCommand blamer = new BlameCommand(<yourRepository>);
    ObjectId commitToBlameID = commitToBlame.getId();
    blamer.setStartCommit(commitToBlameID);
    blamer.setFilePath(path);
    return blamer.call();
}

...或者在给定的时间范围内递归，像这样:

public List<Blame> recuriveBlame(String path, RevCommit beginRevision, RevCommit endRevision) throws IOException, GitAPIException {
   if (path == null
            || beginRevision == null
            || endRevision == null) {
        return null;
    }

    List<Blame> result = new ArrayList<Blame>();
    try (RevWalk rw = new RevWalk(this.repo)) {
        rw.markStart(rw.parseCommit(this.beginRevision));
        rw.markUninteresting(rw.parseCommit(this.endRevision));
        for (RevCommit curr; (curr = rw.next()) != null;){
            result.add(new Blame(curr, blameCommit(path, curr)));
        }
    }

    return result;
}

... 并获取给定提交中给定文件的给定行的提交者，例如 this :

public void printCommitter(Repository repo, ObjectID commitID, String filename){
   int lines = countFiles(repos, commitID, filename);
   for (int i = 0; i < lines; i++) {
       PersonIdent committer = blame.getSourceCommitter(i);
       System.out.println("Committer of the line: " + i + ": " + committer.getName());
   }
}

ps:请注意，您可能需要进行小的更改才能运行此代码。例如，countFiles(...)是here .

https://stackoverflow.com/questions/33296443/