我有一个包含多个配置文件的 json 文件:
{
"profile1": {
"user": "user1",
"channel": "channel1",
"hook": "hook1"
},
"default": {
"user": "user1",
"channel": "channel1",
"hook": "hook2"
}
}
我想使用 jq 插入另一个配置文件“测试”,这样最终结果将是
{
"profile1": {
"user": "user1",
"channel": "channel1",
"hook": "hook1"
},
"default": {
"user": "user1",
"channel": "channel1",
"hook": "hook2"
},
"test": {
"user": "user3",
"channel": "channel3",
"hook": "hook3"
}
}
我可以直接在命令行中使用:
cat filename |
jq '.+ { "test": { "user": "u3", "channel" : "c3", "hook": "w3" } }'
但是当我在我的 bash 脚本中尝试它时:
cat "$CONF_FILE" |
jq --arg p "$PROFILE" --arg u "$U" --arg c "$C" --arg w "$WH" \
'.+ { $p: { "user": $u, "channel": $c, "hook": $w } }' `
我收到以下错误:
jq: error: syntax error, unexpected ':', expecting '}' (Unix shell quoting issues?) at <top-level>, line 1:
.+ { $p: { "user": $u, "channel": $c, "hook": $w } }
jq: error: syntax error, unexpected '}', expecting $end (Unix shell quoting issues?) at <top-level>, line 1:
.+ { $p: { "user": $u, "channel": $c, "hook": $w } }
jq: 2 compile errors
我尝试用引号将变量括起来,但我得到的只是字符串 $p:
cat "$CONF_FILE" |
jq --arg p "$PROFILE" --arg u "$U" --arg c "$C" --arg w "$WH" \
'.+ { "$p": { "user": $u, "channel": $c, "hook": $w } }'
结果:
{
"profile1": {
"user": "user1",
"channel": "channel1",
"hook": "hook1"
},
"default": {
"user": "user1",
"channel": "channel1",
"hook": "hook2"
},
"$p": {
"user": "user3",
"channel": "channel3",
"hook": "hook3"
}
}
编辑:我找到了一个临时解决方案,将对象转换为数组,编辑值(现在配置文件名称是一个值而不是键)并将数组转换回一个对象:
cat "$CONF_FILE" |
jq --arg p "$PROFILE" --arg u "$U" --arg c "$C" --arg w "$WH" \
'to_entries | .+ [ { "key": $p, "value": { "user": $u, "channel": $c, "hook": $w } } ] | from_entries'
这看起来很粗糙,但它确实有效。我仍然希望有更好的解决方案...
最佳答案
在动态键周围使用括号:
jq --arg p "$PROFILE" --arg u "$U" --arg c "$C" --arg w "$WH" \
'. + {($p): {"user": $u, "channel": $c, "hook": $w}}' "$CONF_FILE"
https://stackoverflow.com/questions/37904796/