我正在尝试反序列化从网络调用中获得的 json 响应。我已经知道了 90%。我很难弄清楚的唯一部分是这些 json 数组中包含数据，并且每个数组名称使用电子邮件地址都是唯一的。我一直无法弄清楚如何将电子邮件数组转换为 1. 动态并让它创建许多列表或仅创建几个列表，具体取决于响应中返回的内容，并动态命名列表数组以将数据放入记录中类。

正如您在 Records 类中看到的那样，我需要它更加动态和灵活以接收任何和所有电子邮件。

下面是json:

{
  "result": {
    "records": {
      "joeblow@gmail.com": [
        {
          "OrderId": "d9535109-d305-4584-a503-8194bbcfcff2",
          "CompletedOrderId": "BCFCFF2",
          "CustomerId": 1212,
          "CompletedTime": "2020-10-26 13:32:02",
          "Email": "joeblow@gmail.com",
          "ShippingFirstName": "Joe",
          "ShippingMiddleName": "",
          "ShippingLastName": "Blow",
          "LineItems": {
            "tfl.es.bluray": { "qty": 1 },
            "booklets.en.ebook": { "qty": 1 }
          }
        }
      ],
      "cleob@hotmail.com": [
        {
          "OrderId": "7bf97b3a-bc46-411c-bc30-12563326dba0",
          "CompletedOrderId": "326DBA0",
          "CustomerId": 1212,
          "CompletedTime": "2020-10-26 20:07:44",
          "Email": "cleob@hotmail.com",
          "ShippingFirstName": "Cleo",
          "ShippingMiddleName": "",
          "ShippingLastName": "Blue",
          "LineItems": {
            "tfl.es.bluray": { "qty": 1 },
            "booklets.en.ebook": { "qty": 1 },
            "aos.en.pb": { "qty": 1 },
            "course-tos.en.olr": { "qty": 1 },
            "pow-hsk-nofilm.en.combo": { "qty": 1 },
            "course-organizing.en.olr": { "qty": 1 }
          }
        }
      ],
      "johnd@gmail.com": [
        {
          "OrderId": "630f0dda-94c3-4b82-a070-2554004dce29",
          "CompletedOrderId": "04DCE29",
          "CustomerId": 12345,
          "CompletedTime": "2020-10-25 21:52:04",
          "Email": "johnd@gmail.com",
          "ShippingFirstName": "John",
          "ShippingMiddleName": "",
          "ShippingLastName": "Doe",
          "LineItems": {
            "tfl.es.bluray": { "qty": 1 },
            "booklets.en.ebook": { "qty": 1 },
            "aos.en.pb": { "qty": 1 },
            "course-tos.en.olr": { "qty": 1 },
            "pow-hsk-nofilm.en.combo": { "qty": 1 },
            "course-organizing.en.olr": { "qty": 1 },
            "oak-2007.en.cd": { "qty": 1 }
          }
        }
      ]
    },
    "errors": [
      {
        "id": "bademailaddress-yahoo.com",
        "message": "Email address 'bademailaddress-yahoo.com' is not a valid email address"
      }
    ]
  },
  "jsonrpc": "2.0",
  "id": 12345634523
} 

以及我为 json 反序列化制作的类:

public partial class JsonEmailDeSerializer
{
    [JsonProperty("result")]
    public Result Result { get; set; }

    [JsonProperty("jsonrpc")]
    public string Jsonrpc { get; set; }

    [JsonProperty("id")]
    public long Id { get; set; }
}

public partial class Result
{
    [JsonProperty("records")]
    public Records Records { get; set; }

    [JsonProperty("errors")]
    public List<Error> Errors { get; set; }
}

public partial class Error
{
    [JsonProperty("id")]
    public string Id { get; set; }

    [JsonProperty("message")]
    public string Message { get; set; }
}

public partial class Records
{
    [JsonProperty("joeblow@gmail.com")]
    public List<MailCom> JoeblowGmailCom { get; set; }

    [JsonProperty("cleob@hotmail.com")]
    public List<MailCom> CleobHotmailCom { get; set; }

    [JsonProperty("johnd@gmail.com")]
    public List<MailCom> JohndGmailCom { get; set; }
}

public partial class MailCom
{
    [JsonProperty("OrderId")]
    public Guid OrderId { get; set; }

    [JsonProperty("CompletedOrderId")]
    public string CompletedOrderId { get; set; }

    [JsonProperty("CustomerId")]
    public long CustomerId { get; set; }

    [JsonProperty("CompletedTime")]
    public DateTimeOffset CompletedTime { get; set; }

    [JsonProperty("Email")]
    public string Email { get; set; }

    [JsonProperty("ShippingFirstName")]
    public string ShippingFirstName { get; set; }

    [JsonProperty("ShippingMiddleName")]
    public string ShippingMiddleName { get; set; }

    [JsonProperty("ShippingLastName")]
    public string ShippingLastName { get; set; }

    [JsonProperty("LineItems")]
    public Dictionary<string, LineItem> LineItems { get; set; }
}

public partial class LineItem
{
    [JsonProperty("qty")]
    public long Qty { get; set; }
}

public partial class JsonEmailDeSerializer
{
    public static JsonEmailDeSerializer FromJson(string json) => JsonConvert.DeserializeObject<JsonEmailDeSerializer>(json, FedExShipper.Converter.Settings);
}

public static class Serialize
{
    public static string ToJson(this JsonEmailDeSerializer self) => JsonConvert.SerializeObject(self, FedExShipper.Converter.Settings);
}

internal static class Converter
{
    public static readonly JsonSerializerSettings Settings = new JsonSerializerSettings
    {
        MetadataPropertyHandling = MetadataPropertyHandling.Ignore,
        DateParseHandling = DateParseHandling.None,
        Converters =
        {
            new IsoDateTimeConverter { DateTimeStyles = DateTimeStyles.AssumeUniversal }
        },
    };
}

最佳答案

使用动态属性名称反序列化 json 的常用方法是使用 Dictionary<string, ...> , 在这种情况下 - Dictionary<string, List<MailCom>>可用于 Records属性:

public partial class Result
{
    [JsonProperty("records")]
    public Dictionary<string, List<MailCom>> Records { get; set; }

    [JsonProperty("errors")]
    public List<Error> Errors { get; set; }
}

Json.NET 可以处理 json 对象属性 as keys for dictionary这使得它适合反序列化此类动态数据。 System.Text.Json也是如此.

https://stackoverflow.com/questions/65118056/